(2x+5)(x+3)=2x^2+7x-5

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Solution for (2x+5)(x+3)=2x^2+7x-5 equation: 



(2x+5)(x+3)=2x^2+7x-5

We move all terms to the left:

(2x+5)(x+3)-(2x^2+7x-5)=0

We get rid of parentheses

-2x^2+(2x+5)(x+3)-7x+5=0

We multiply parentheses ..

-2x^2+(+2x^2+6x+5x+15)-7x+5=0

We get rid of parentheses

-2x^2+2x^2+6x+5x-7x+15+5=0

We add all the numbers together, and all the variables

4x+20=0

We move all terms containing x to the left, all other terms to the right

4x=-20

x=-20/4

x=-5

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